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Find the x-intercept and y-intercept of the line. -3x+6y=11

Sagot :

Answer:

x- intercept is at [tex]( - 3 \frac{2}{3} ,0)[/tex].

y- intercept is at [tex](0,1 \frac{5}{6} )[/tex].

Step-by-step explanation:

The x-intercept occurs when y=0.

Thus, substitute y= 0 into the equation to find the x- intercept.

-3x +6y= 11

When y= 0,

-3x +6(0)= 11

-3x= 11

x= 11 ÷ (-3)

[tex]x = - \frac{11}{3} \\ x = - 3 \frac{2}{3} [/tex]

The y-intercept occurs at x= 0.

When x= 0,

-3(0) +6y= 11

6y= 11

y= 11÷ 6

[tex]y = 1\frac{5}{6} [/tex]