Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Answer:
The kinetic energy of the boy is 20 times that of the kinetic energy of the girl.
Explanation:
It is given that,
The mass of the boy is 20 times that of girl.
Let [tex]m_b[/tex] and [tex]m_g[/tex] are the mases of boy and the girls.
A boy and girl are running with the same speed.
The formula for the kinetic energy is given by :
[tex]E=\dfrac{1}{2}mv^2[/tex]
Where m is mass and v is speed
As speed is same for both boy and girl.
Kinetic energy of a girl,
[tex]K_g=\dfrac{1}{2}m_gv^2[/tex] ...(1)
As [tex]m_b=20m_g[/tex]
Kinetic energy of a boy,
[tex]K_b=\dfrac{1}{2}m_bv^2\\\\=\dfrac{1}{2}\times 20m_g\times v^2\ ....(2)[/tex]
From equation (1) and (2) :
[tex]\dfrac{K_g}{K_b}=\dfrac{\dfrac{1}{2}m_gv^2}{\dfrac{1}{2}m_bv^2}\\\\=\dfrac{\dfrac{1}{2}m_gv^2}{\dfrac{1}{2}\times 20 m_gv^2}\\\\\dfrac{K_g}{K_b}=\dfrac{1}{20}\\\\K_b=20K_g[/tex]
So, the kinetic energy of the boy is 20 times that of the kinetic energy of the girl. Hence, this is the required solution.
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
