Answered

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Find the solution set of the inequality. \qquad16x - 7 \leq -7116x−7≤−71

Sagot :

MrRoyal

Answer:

[tex]x \le -4[/tex]

Step-by-step explanation:

Given

[tex]\qquad16x - 7 \leq -71[/tex]

Required

Solve

Start by adding 7 to both sides

[tex]\qquad16x - 7 + 7 \leq -71 + 7[/tex]

[tex]\qquad16x - 7 + 7 \leq -64[/tex]

[tex]\qquad16x \leq -64[/tex]

Divide both sides by 16

[tex]\frac{16x}{16} \leq \frac{-64}{16}[/tex]

[tex]\frac{16x}{16} \leq -\frac{64}{16}[/tex]

[tex]x \leq -\frac{64}{16}[/tex]

[tex]x \le -4[/tex] --- The solution

therealwillywonka

Answer:

x < -4

I did this on khan academy

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