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How many 7 digit numbers have6 9 s and no 9 in ones place

Sagot :

Answer:

1062882

Step-by-step explanation:

Seven digits numbers, with repetition of digits, having 6 or 9 at the last one's place :

The first six digits can be filled with 9 options each (numbers 1 to 9) , & the last digit can be filled with 2 options (number 6 & 9)

So, total 7 digit numbers as per given condition = 9 x 9 x 9 x 9 x 9 x 9 x 9 x 2 = 1062882

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