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a 2kg box frictionless ramp angle 60 degrees top of ramp is 30 m how long will it take to reach the ground

Sagot :

abidemiokin

Answer:

2.66secs

Explanation:

To get the time it will take to reach the ground, we will use the equation of motion;

S = ut + 1/2at²

S is the distance

u is the initial velocity

g is the acceleration due to gravity

Given

S = 30m

u = 0m/s

Let's get the acceleration

According to newton's second law;

[tex]\F_x = ma_x\\F_m - F_f = ma_x\\mgsin \theta - 0 = ma_x\\gsin\theta = a_x\\a_x = 9.8sin 60\\a_x = 9.8(0.8660)\\a_x = 8.49m/s^2[/tex]

Get the required time:

Recall that: S = ut + 1/2at²

Substitute the given parameters and find t

30 = 0(t) + 1/2(8.49)t²

30 = 4.24t²

t² = 30/4.24

t² = 7.08

t = √7.08

t = 2.66secs

Hence it take the box 2.66seconds to reach the ground

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