ShahanaRajasekar
Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

If p = 3sec theta and q= 3 tan^2 theta - 1, then find p-q. ​

Sagot :

Answer:

[tex]p - q = 3 \sec\theta - (3 { \tan}^{2} \theta - 1) \\ = 3 \sec \theta - 3 { \tan}^{2} \theta + 1 \\ from \: identities \: \: { \tan }^{2} \theta + 1 = { \sec }^{2} \theta \\ = 3 { \sec } \theta - 3( { \sec }^{2} \theta - 1) + 1 \\ = 3 \sec\theta - 3 { \sec}^{2} \theta + 3 + 1 \\ = - 3 { \sec }^{2} \theta + 3 \sec\theta + 4 \\ = - 3( { \sec}^{2} \theta - \sec \theta - \frac{4}{3} )[/tex]

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.