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Sagot :
Answer:
10.90km
Explanation:
Magnitude of the total displacement is expressed using the equation
d = √dx²+dy²
dx is the horizontal component of the displacement
dy is the vertical component of the displacement
dy = -6.7sin27°
dy = -6.7(0.4539)
dy = -3.042
For the horizontal component of the displacement
dx = -4.5 - 6.7cos27
dx = -4.5 -5.9697
dx = -10.4697
Get the magnitude of the bicyclist's total displacement
Recall that: d = √dx²+dy²
d = √(-3.042)²+(-10.4697)²
d = √9.2538+109.6146
d = √118.8684
d = 10.90km
Hence the magnitude of the bicyclist's total displacement is 10.90km
The bicyclist magnitude of displacement is equal to 9.62m
Resolution of Vectors
To find the resultant magnitude of the bicyclist total displacement, we have to find the x and y component.
For the first direction, the components are
[tex]x_1 = -4.5i[/tex]
sine we don't have any vertical displacement, the y-component is equal to zero.
for the second direction,
[tex]x_2 = -6.7sin27i\\y_2= 6.7cos27j[/tex]
The resultant x and y component are;
- [tex]R_x = -4.5i + (-6.7sin27i)\\R_x = -7.54i[/tex]
- [tex]R_y = 0 + 6.7cos27= 5.97j[/tex]
Let's find the magnitude of displacement
[tex]R = \sqrt{R_x^2 + R_x^2}\\R = \sqrt{(-7.54)^2 + (5.97)^2 }\\\\R = 9.62m[/tex]
The bicyclist magnitude of displacement is equal to 9.62m
Learn more on resolution of vectors here;
https://brainly.in/question/3543542
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