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A baseball team has a 20-person roster. A batting order has nine people. How many different batting orders are there

Sagot :

Answer:

60,949,324,800

Step-by-step explanation:

We solve the above question using Permutation formula

The formula for Permutation =

nPr = n!/(n - r)!

Total Amount in a Set (n) = 20 persons

Amount in each Sub-Set (r) = 9 batting order

Hence:

20P9 = 20!/(20 - 9)!

= 60,949,324,800

Therefore, the different batting orders they would have are: 60,949,324,800

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