Answered

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use elimination to solve each system below:

system 1 system 2
4x+3y=4 3x+2y=7
-2x-3y=-8 2x-y=7
enter the value of x and y in the solution for each in the following table
value of x value of y
system 1
system 2

Sagot :

Answer:

SYSTEM 1

[tex]4x + 3y = 4 - - - eqn(i) \\ - 2x - 3y = - 8 - - - eqn(ii) \\ eqn(i) + eqn(ii) \\ = > 4x - 2x = 4 - 8 \\ 2x = - 4 \\ x = \frac{ - 4}{2} \\ x = - 2 \\ in \: eqn(i) \: \: 4x + 3y = 4 \\ but \: x = - 2 \\ = > 4( - 2) + 3y = 4 \\ = > - 8 + 3y = 4 \\ 3y = 12 \\ y = \frac{12}{3} \\ y = 4[/tex]

SYSTEM 2

[tex]3x + 2y = 7 - - - eqn(i) \\ 2x - y = 7 - - - eqn(ii) \\ multiply \: eqn(ii) \: by \: 2 \\ = > 4x - 2y = 14 - - - eqn(iii) \\ eqn(i) + eqn(iii) \\ = > 7x = 21 \\ x = \frac{21}{7} \\ x = 3 \\ in \: eqn(ii) \: 2x - y = 7 \\ but \: x = 3 \\ hence \: \: 2(3) - y = 7 \\ y = 6 - 7 \\ y = - 1[/tex]

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