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Find the 13Th term of geometric sequence 1,2,4,

Sagot :

Answer:

a₁₃ = 4096

Step-by-step explanation:

The n th term of a geometric sequence is

[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]

where a₁ is the first term and r the common ratio

Here a₁ = 1 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{2}{1}[/tex] = 2 , then

a₁₃ = 1 × [tex]2^{12}[/tex] = 4096