Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

I want to prepare 4 Liters of 0.25 M aqueous sodium chloride solution. How many grams of the salt will I need to weigh out?

Sagot :

Neetoo

Answer:

Mass = 58.5 g

Explanation:

Given data:

Volume of solution = 4 L

Molarity of solution = 0.25 M

Grams of NaCl required = ?

Solution:

Formula:

Molarity = number of moles / volume in L

By putting values,

0.25 M = number of moles / 4 L

Number of moles = 0.25 mol/L × 4 L

Number of moles = 1 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 1 mol × 58.5 g/mol

Mass = 58.5 g

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.