Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

How many mL of 0.105 M aqueous NaOH solution are required to neutralize 40.0 mL of 0.210 M aqueous H2SO4 solution?

H 2SO 4 + 2 NaOH ---> Na 2SO 4 + 2 H 2O

Sagot :

Neetoo

Answer:

160 mL

Explanation:

Given data:

Molarity of NaOH = 0.105 M

Volume of H₂SO₄ = 40.0 mL (40.0/1000 = 0.04 L)

Molarity of H₂SO₄ = 0.210 M

Volume of NaOH required = ?

Solution:

Number of moles of of H₂SO₄:

Molarity = number of moles / volume in L

0.210 M = number of moles / 0.04 L

Number of moles = 0.210 mol/L × 0.04 L

Number of moles = 0.0084 mol

now we will compare the moles of H₂SO₄  with NaOH.

                     H₂SO₄          :           NaOH

                        1                 :             2

                    0.0084          :         2/1×0.0084 = 0.0168 mol

Volume of NaoH:

Molarity = number of moles / volume in L

0.105 M =  0.0168 mol / Volume in L

Volume in L =  0.0168 mol / 0.105 M

Volume in L =  0.16 L

Volume in mL:

0.16 L × 1000 mL/ 1L

160 mL

Eduard22sly

The volume of the NaOH solution required for the reaction is 160 mL

The balanced equation for the reaction is given below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₂SO₄ (nA) = 1
  • The mole ratio of the base, NaOH (nB) = 2

Finally, we shall determine the volume of the base, NaOH required for the reaction.

  • Molarity of the base, NaOH (Mb) = 0.105 M
  • Volume of the acid, H₂SO₄ (Va) = 40 mL
  • Molarity of the acid, H₂SO₄ (Ma) = 0.210 M
  • Volume of the base, NaOH (Vb) =?

MaVa / MbVb = nA/nB

(0.21 × 40) / (0.105 × Vb) = 1 / 2

8.4 / (0.105 × Vb) = 1 / 2

Cross multiply

0.105 × Vb = 8.4 × 2

0.105 × Vb = 16.8

Divide both side by 0.105

Vb = 16.8 / 0.105

Vb = 160 mL

Thus, the volume of the base, NaOH required for the reaction is 160 mL

Learn more about stoichiometry: https://brainly.com/question/21182105

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.