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Sagot :
Answer:
[tex]let \: the \: inverse \: of \: f(x) \: be \: m \\ m = {f(x)}^{ - 1} \\ m = {(4x + 12)}^{ - 1} \\ m = \frac{1}{(4x + 12)} \\ m(4x + 12) = 1 \\ 4x = \frac{1}{m} - 12 \\ x = \frac{1}{4m} - 3 \\ therefore \\ g(x) = \frac{1}{4x} - 3[/tex]
Answer:
g(x) = 1/4 x -3
Step-by-step explanation:
f (x) = 4 x + 12
g(x) = f⁻¹(x)
step 1: re-write as linear equation y = 4x+12
step 2: swap x and y x = 4y + 12
step 3: solve y 4y = x - 12 y = 1/4 x -3
step 4: inverse notation: f⁻¹(x) = 1/4 x - 3 i.e. g(x) = 1/4 x -3
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