Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

I'm doing a extra credit worksheet for math it says “Graph the following equation (Don’t forget to get y alone first, then use the slope and y-intercept to graph” the equation I’m doing right now is y= 1/2x + 18 can somebody please help me

Sagot :

9514 1404 393

Answer:

  see below for a graph

Step-by-step explanation:

Your equation has "y alone". It is written in "slope-intercept form."

  y = mx + b . . . . . . . where m is the slope and b is the y-intercept.

Comparing your given equation ...

  y = 1/2x + 18

to the above form you see that m = 1/2 (the slope) and b = 18 (the y-intercept).

The y-intercept is where the graph crosses the y-axis, so the first point you can plot on the graph is at (0, 18) on the y-axis.

The slope of 1/2 tells you the ratio of "rise" to "run" is 1/2. That is, the "run" (change in x) is 2 units for each "rise" (change in y) of 1 units

  m = rise/run = 1/2

So, another point (or several) can be found by moving twice as many units to the right as you move up. For example, if you choose 10 units right, to x=10, the point will be 10/2 = 5 units up from y=18, at y = 23. That is (10, 23) is another point on the graph.

Now, you have points (0, 18) and (10, 23) on the line. The graph will be a straight line through those points.

View image sqdancefan
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.