littleoneinaz
Answered

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Which of the following statements have the same result? Explain each step in solving each one.
I. f(1) when f(x) = 4x - 1
II. F-1(2) when f(x) =
3x – 1/4
III. 2y + 8 = 4y - 2

Sagot :

Answer:

Non of the above

I

[tex]f(x) = 4x - 1 \\ f(1) = 4 - 1 \\ f(1) = 3[/tex]

II

[tex]f(x) = 3x - \frac{1}{4} \\ {f}^{ - 1} (x) = \frac{1}{3x} + \frac{1}{12} \\ {f}^{ - 1} (2) = \frac{1}{6} + \frac{1}{12} \\ {f}^{ - 1} (2) = \frac{1}{4} [/tex]

III

[tex]2y + 8 = 4y - 2 \\ - 2y = - 10 \\ y = 5[/tex]

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