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Given z1=9+9sqrt(3)i and z2=2+sqrt(3)i what is z2-z1
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Sagot :

Answer:

[tex] = 2 + \sqrt{3} i - (9 + 9 \sqrt{3} i) \\ = (2 - 9) + ( \sqrt{3} - 9 \sqrt{3} )i \\ = - 7 + (1 - 9) \sqrt{3} i \\ = - 7 - 8 \sqrt{3} i[/tex]

The required simplification of z2-z1 = -7-8sqrt(3)i.

z1=9+9sqrt(3)i
z2=2+sqrt(3)i
z2-z1 to be determined.

What is a complex number?

A complex number is defined as the sum of a real and imaginary numbers.

Here,
[tex]z_1=9+9\sqrt(3)i\\z_2=2+\sqrt(3)i\\\\z_2-z_1 = 2+\sqrt(3)i-(9+9\sqrt3i\\z_2-z_1 = 2-9+\sqrt(3)i-9\sqrt3i\\z_2-z_1 = -7-8\sqrt(3)i[/tex]

Thus, the required simplification of z2-z1 = -7-8sqr(3)i.


Learn more about complex numbers here:

https://brainly.com/question/28007020
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