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What is the product of 2(cos(45°) + i sin(45°)) and 5(cos(30°) + i sin(30°))?
Pls help


Sagot :

Answer:

[tex]10(\cos 75^\circ+\mathbf{i}\sin 75^\circ)[/tex]

Step-by-step explanation:

Complex Numbers

Complex numbers can be expressed in several forms. One of them is the rectangular form(x,y):

[tex]Z = x+\mathbf{i}y[/tex]

Where

[tex]\mathbf{i}=\sqrt{-1}[/tex]

They can also be expressed in polar form (r,θ):

[tex]Z=r(\cos\theta+\mathbf{i}\sin\theta)[/tex]

The polar form is also shortened to:

[tex]Z = r CiS(\theta)[/tex]

The product of two complex numbers in polar form is:

[tex][r_1Cis(\theta_1)]\cdot [r_2Cis(\theta_2)]=r_1\cdot r_2Cis(\theta_1+\theta_2)[/tex]

We are given the complex numbers:

2(cos(45°) + i sin(45°)) and 5(cos(30°) + i sin(30°))

They can be written as:

2CiS(45°) and 5CiS(30°). The product is:

2CiS(45°) * 5CiS(30°) = 10CiS(75°)

Expressing back in rectangular form:

[tex]\boxed{2CiS(45^\circ) \cdot 5CiS(30^\circ) =10(\cos 75^\circ+\mathbf{i}\sin 75^\circ)}[/tex]

Answer:

10, 75, 75 on edge

Step-by-step explanation: