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How many moles of HCI are neede to prepare 150 mL of a 1.2 M
solution?​

Sagot :

Space

Answer:

0.18 moles HCl

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Unit 0

  • Conversion: 1000 mL = 1 L

Aqueous Solutions

  • Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define

150 mL

1.2 M

x moles

Step 2: Identify Conversions

mL to L conversion

Step 3: Convert

[tex]\displaystyle 150 \ mL(\frac{1 \ L}{1000 \ mL} )[/tex] = 0.15 L

Step 4: Solve for Moles

  1. Substitute [Molarity]:                    [tex]\displaystyle 1.2 \ M = \frac{x \ moles \ HCl}{0.15 \ L}[/tex]
  2. Isolate x:                                       [tex]\displaystyle 0.18 \ moles \ HCl = x[/tex]
  3. Rewrite:                                        [tex]\displaystyle x = 0.18 \ moles \ HCl[/tex]

Step 5: Check

We are given 2 sig figs. Follow sig fig rules and round.

Since our final answer is in 2 sig figs, there is no need to round.

Answer:

0.18 moles HCl

Explanation:

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