Answer:
the length of the minute hand is 36/100 . 150 = 54 (mm)
y is the distance between the minute hand and the hour hand now
x is the angle beween the minute hand and the hour hand, so we have:
cos x = 36/54 = 2/3 => sin x = [tex]\sqrt{1-(\frac{2}{3})^{2} }=\frac{\sqrt{5} }{3}=\frac{y}{54}[/tex] => y = 18√5 (mm)
a) see in the ques, u can see that in 45', the minute hand will move a distance equal to 2 times its length and a distance = 2.18√5 (mm)
=> the distance which the minute hand will move is 54.2 + 2.18√5 = 188,50 (mm)
b) the distance which the minute hand will move in 1h is 54.4 - 18√5 = 175,75(mm)
the distance which the hour hand will move in 1h is 36.4 = 144 (mm)
=> the minute hand will move: 175,75 - 144 = 31,75(mm) further than the hour hand
Step-by-step explanation: