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Sagot :
Answer:
a = -2.57 and b = 2.57
Step-by-step explanation:
Explanation:
Given mean of the Population = 212
Standard deviation of the Population = 122
Let X be the random variable of the Normal distribution
[tex]Z = \frac{x-mean}{S.D}[/tex]
Given P( a ≤ z ≤b) = 0.99
put a=-b
P( -b ≤ z ≤b) = 0.99
⇒ |A( b) - A( -b)| =0.99
⇒ | A( b) + A( b)| =0.99
⇒ 2 |A (b)| = 0.99
⇒ | A(b)| = 0.495
From normal table find value in areas
b = 2.57 ( see in normal table)
Given a =-b
a = - 2.57
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