Answered

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Suppose that the grades of Business Mathematics and Statistic module is modeled well
by a normal probability distribution with mean (212) and standard deviation (122). Let
X be the random variable representing this distribution. Find two symmetric values "a"
and "b" such that Probability [ a

Sagot :

Answer:

a = -2.57 and b = 2.57

Step-by-step explanation:

Explanation:

Given mean of the Population = 212

Standard deviation of the Population = 122

Let  X be the random variable of the Normal distribution

[tex]Z = \frac{x-mean}{S.D}[/tex]

Given P( a ≤ z ≤b) = 0.99

  put a=-b

         P( -b ≤ z ≤b) = 0.99

   ⇒     |A( b) - A( -b)| =0.99

    ⇒     | A( b) + A( b)| =0.99  

   ⇒       2 |A (b)| = 0.99

     ⇒     | A(b)| = 0.495

From normal table find value in areas

          b = 2.57 ( see in  normal table)

         Given a =-b

                   a = - 2.57

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