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Sagot :
Answer:
O = 57.14%
C = 42.86%
Explanation:
First of all we will calculate the molar mass of CO.
C = 12 g/mol
O = 16 g/mol
CO = 12 g/mol + 16 g/mol
CO = 28 g/mol
Percent composition:
C = (12 g/mol /28 g/mol ) × 100
C = 42.86%
O = (16 g/mol /28 g/mol ) × 100
O = 57.14%
Answer:
it should be 42.86% carbon and 57.14% oxygen
C = 12
O = 16
CO = 12 + 16
CO = 28
C = (12 /28 ) × 100
C = 42.86%
O = (16 /28 ) × 100
O = 57.14%
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