thoronkayamana
Answered

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The sum of an arithmetic progression A.P.
The sum of an arithmetic progression is
given by the expression:
Sn = n/2 [2a + (n − 1)d]
Where Sn is the sum.​

Sagot :

abidemiokin

Answer:

S8 = 112

Step-by-step explanation:.​

The question is incomplete

Assuming we are given the following

First term a =7

number of terms n = 8.

Common difference d=2

We can find the sum of the first 8terms S8

Substitute the given values

S8 = 8/2[2(7)+(8-1)(2)]

S8 =4(14+7(2))

S8=4(14+14)

S8 = 4(28)

S8 = 112

Hence the sum of the first 8terms is 112

Note that the values are assumed values

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