Answer:
h = 104.13 m
Explanation:
Given that,
Horizontal velocity of the car, v = 13 m/s
It hits the ground 60 m from the shoreline
We need to find the height of the cliff. Let t be the time of fall. We can find it as follows :
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{60\ m}{13\ m/s}\\\\t=4.61\ s[/tex]
So, the time of fall is 4.61 seconds.
Let h is the height of the cilff. Using second equation of motion to find it as follows :
[tex]h=\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times 4.61^2\\\\=104.13\ m[/tex]
So, the height of the cliff is 104.13 m.
The height of the cliff from which the car rolls off is 104.59 m
We'll begin by calculating the the time taken for the car to reach the ground.
Horizontal distance (s) = 60 m
Horizontal velocity (u) = 13 m/s
[tex]t = \frac{s}{u} \\ \\ t = \frac{60}{13} \\ [/tex]
t = 4.62 s
Thus, the time taken for the car to reach the ground is 4.62 s
Time (t) = 4.62 s
Acceleration due to gravity (g) = 9.8 m/s²
h = ½gt²
h = ½ × 9.8 × 4.62²
Therefore, the height of the cliff is 104.59 m
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