Pebbles2008
Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Use the diagram below to find the lengths of the missing sides. Figures in each diagram are similar.

X=15
X=10
X=40
X=30

Use The Diagram Below To Find The Lengths Of The Missing Sides Figures In Each Diagram Are Similar X15 X10 X40 X30 class=

Sagot :

jamyangnorzin

DE/AB=DF/AC

10/5=DF/15

=10×15=5DF

=150=5DF

DF=150÷5

=30

gmany

Answer:

Such triangles do not exist.

Step-by-step explanation:

There is some mistake in your question.

We know:

In any triangle with sides a, b and c:

a + b > c

a + c > b

b + c > a

In your question the triangle ABC has:

a = 5, b = 10, c = 15

then

5 + 10 = 15 not > 15.

a + b = c not > c.

In my opinion, the question makes no mathematical sense.

Nevertheless, the moderator asked me to correct my answer.

If two triangles are similar, then corresponding sides are in proportion.

[tex]\dfrac{10}{5}=\dfrac{20}{10}=\dfrac{x}{15}\\\\2=2=\dfrac{x}{15}\\\\\dfrac{x}{15}=2\Rightarrow x=30[/tex]

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.