Pebbles2008
Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Use the diagram below to find the lengths of the missing sides. Figures in each diagram are similar.

X=15
X=10
X=40
X=30

Use The Diagram Below To Find The Lengths Of The Missing Sides Figures In Each Diagram Are Similar X15 X10 X40 X30 class=

Sagot :

jamyangnorzin

DE/AB=DF/AC

10/5=DF/15

=10×15=5DF

=150=5DF

DF=150÷5

=30

gmany

Answer:

Such triangles do not exist.

Step-by-step explanation:

There is some mistake in your question.

We know:

In any triangle with sides a, b and c:

a + b > c

a + c > b

b + c > a

In your question the triangle ABC has:

a = 5, b = 10, c = 15

then

5 + 10 = 15 not > 15.

a + b = c not > c.

In my opinion, the question makes no mathematical sense.

Nevertheless, the moderator asked me to correct my answer.

If two triangles are similar, then corresponding sides are in proportion.

[tex]\dfrac{10}{5}=\dfrac{20}{10}=\dfrac{x}{15}\\\\2=2=\dfrac{x}{15}\\\\\dfrac{x}{15}=2\Rightarrow x=30[/tex]

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.