Pebbles2008
Answered

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Use the diagram below to find the lengths of the missing sides. Figures in each diagram are similar.

X=15
X=10
X=40
X=30

Use The Diagram Below To Find The Lengths Of The Missing Sides Figures In Each Diagram Are Similar X15 X10 X40 X30 class=

Sagot :

jamyangnorzin

DE/AB=DF/AC

10/5=DF/15

=10×15=5DF

=150=5DF

DF=150÷5

=30

gmany

Answer:

Such triangles do not exist.

Step-by-step explanation:

There is some mistake in your question.

We know:

In any triangle with sides a, b and c:

a + b > c

a + c > b

b + c > a

In your question the triangle ABC has:

a = 5, b = 10, c = 15

then

5 + 10 = 15 not > 15.

a + b = c not > c.

In my opinion, the question makes no mathematical sense.

Nevertheless, the moderator asked me to correct my answer.

If two triangles are similar, then corresponding sides are in proportion.

[tex]\dfrac{10}{5}=\dfrac{20}{10}=\dfrac{x}{15}\\\\2=2=\dfrac{x}{15}\\\\\dfrac{x}{15}=2\Rightarrow x=30[/tex]

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