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-4n + 1/3m + 4n - 4/5m​

Sagot :

absor201

Answer:

[tex]-4n+\frac{1}{3m}+4n-\frac{4}{5m}=-\frac{7}{15m}[/tex]        

Step-by-step explanation:

Given the expression

[tex]-4n\:+\:\frac{1}{3m}\:+\:4n\:-\frac{4}{5m}[/tex]

Group like terms

[tex]-4n\:+\:\frac{1}{3m}\:+\:4n\:-\frac{4}{5m}=-4n+4n+\frac{1}{3m}-\frac{4}{5m}[/tex]

Adding similar elements: -4n + 4n = 0

                                      [tex]=\frac{1}{3m}-\frac{4}{5m}[/tex]          

L.C.M of 3m and 5n will be: 15m

so adjusting fractions based on the LCM

                                       [tex]=\frac{5}{15m}-\frac{12}{15m}[/tex]      

Since, the denominators are equal, combine the fractions:  [tex]\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}[/tex]

                                       [tex]=\frac{5-12}{15m}[/tex]

                                       [tex]=\frac{-7}{15m}[/tex]

                                       [tex]=-\frac{7}{15m}[/tex]

Therefore, we conclude that:

[tex]-4n+\frac{1}{3m}+4n-\frac{4}{5m}=-\frac{7}{15m}[/tex]                    

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