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What is the net force on a truck if the force of friction is 31 N and the force of the engine is 79 N?

48 N backword

79 N forward

48 N forward

110 N forward​


Sagot :

Answer:

Fr = 48 [N] forward.

Explanation:

Suppose the movement is on the X axis, in this way we have the force of the engine that produces the movement to the right, while the force produced by the brake causes the vehicle to decrease its speed in this way the sign must be negative.

∑F = Fr

[tex]F_{engine}-F_{brake} =F_{r}\\F_{r}=79-31\\F_{r}=48[N][/tex]

The movement remains forward, since the force produced by the movement is greater than the braking force.

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