Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To make 100 ml of 25% saline solution, Riley will need 50 ml = 12% saline mixture and 50 ml= 38% saline mixture.
Given,
We have 12% and 38% of saline mixtures.
We need to find the amount in ml from each saline mixture which would give us 100 ml of 25%.
What are the methods to solve a system of linear equations?
There are a number of methods but the most and easiest used method is the substitution method and the elimination method.
We can make two linear equations from the given statements.
Let x = amount from 12% saline mixture and y = amount from 38% saline mixture.
Now we need to make 100 ml of 25% saline.
so,
x + y = 100.
So we have two equations.
x + y = 100..............(1)
12% of x + 38% of y = 100 x 25%
0.12x + 0.38 = 25 ...............(2)
Using the substitution method we have,
x = 100 - y
Putting x = 100 - y in {2}
0.12 ( 100 - y ) + 0.38y
= 2512 - 0.12y + 0.38y
= 250.38y - 0.12y
= 25 - 120.26y = 13y
= 13 / 0.26y = 50.
Putting y = 50 in (1)
x + y = 100x
100 -50x = 50.
So Riley will need 50 ml = 12% saline mixture and 50ml = 38% saline mixture to make 100 ml of 25% saline solution.
Learn more about finding proportion of mixtures here:
https://brainly.com/question/20366557
#SPJ2
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
