At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

What is the total pressure in units of kPa in a 7.85 L container that contains 4.45 moles of N2 and 2.45 moles of O2 at a temperature of 307 K?

Sagot :

Neetoo

Answer:

Total pressure = 22.15 atm

Explanation:

Given data:

Total pressure = ?

Volume of container = 7.85 L

Number of moles of N₂ = 4.45 mol

Number of moles of O₂ = 2.45 mol

Temperature = 307 K

Solution:

Pressure of N₂:

PV = nRT

P = nRT/V

P = 4.45 mol ×0.0821 atm.L/mol.K ×307K / 7.85L

P = 112.16 atm.L/7.85 L

P = 14.28 atm

Pressure of O₂:

PV = nRT

P = nRT/V

P = 2.45 mol ×0.0821 atm.L/mol.K ×307K / 7.85L

P = 61.75 atm.L/7.85 L

P = 7.87 atm

Total pressure = P(N₂) + P(O₂)

Total pressure = P( 14.28 atm)  +  P( 7.87 atm)

Total pressure = 22.15 atm

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.