Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Jane is riding in a hot air balloon that is rising vertically at a constant speed of 3 m/s over a lake. She drops a rock from the balloon when the distance from the rock to the water is 50 m. Use g m/s^2, and let the up direction be positive. How long after Jane drops the rock will it splash into the water?

Sagot :

It is given that up direction be positive.

Ball velocity at the time is was dropped is 3 m/s.

g = -9.8 m/s²

s = -50 m

Now, using equation of motion for time :

s = ut + at²/2

3t - 4.9t² + 50 = 0

4.9t² - 3t - 50 = 0

Solving above equation, we get :

t = 3.52 s

Therefore, the rock will splash into the water after 3.52 s.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.