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A 3.1 kg block initially at rest is pulled to the right along a horizontal frictionless surface by a constant horizontal force of 16.6 N. Find the speed after it has moved 3.8m.

Sagot :

We know, acceleration is given by :

a = F/m

a = 16.6/3.1 m/s²

a = 5.35 m/s²

Now, we need to find the speed after it has moved 3.8 m.

By equation of motion :

[tex]v^2 -u^2 = 2as\\\\v=\sqrt{2as}\\\\v = \sqrt{2\times 5.35 \times 3.8 }\ m/s\\\\v = 6.38\ m/s[/tex]

Therefore, the speed after it has moved 3.8 m is 6.38 m/s.

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