Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A rigid 7.80 L sealed vessel containing 2.700 mol of O2(g), 0.600 mol of C2H4(g), and 2.400 mol of Ne(g) has an internal temperature of 85.0∘C

a. Calculate the total pressure in the cylinder.
b. Find the mole fraction of O2 in the vessel.
c. A lab technician ignites the mixture in the vessel and the following reaction occurs:

C2H4(g)+3O2(g)→2CO2(g)+2H2O(g)

Find the mole fraction of each gas in the vessel after the reaction.

Sagot :

jufsanabriasa

Answer:

a. 21.46atm

b. 0.4737

c.

Mole fraction O2 = 0.1579

Mole fraction CO2 = 0.2105

Mole fraction H2O 0.2105

Mole fraction Ne = 0.4211

Explanation:

a. To solve the total pressure of the cylinder we need to use:

PV = nRT

Where P is pressure: Our incognite

V is volume: 7.80L

n are total moles: 2.700mol + 0.600mol + 2.400mol = 5.700moles

R is gas constant: 0.082atmL/molK

And T is absolute temperature in K: 85°C + 273.15 = 358.15K

P = nRT/V

P = 5.700mol*0.082atmL/molK*358.15K/7.80L

P = 21.46atm

b. Mole fraction of O2 is the ratio of moles of O2 (2.700mol) over total moles of the mixture (5.700mol).

Mole fraction = 2.700mol / 5.700mol = 0.4737

c. In the reaction:

C2H4(g)+3O2(g)→2CO2(g)+2H2O(g)

For a complete reaction of the 0.600mol of C2H4 there are required:

0.600mol C2H4 * (3 mol O2 / 1mol C2H4) = 1.800 moles of O2

As there are 2.700moles of O2, will remain:

2.700 - 1.800 = 0.900moles of O2

All C2H4 is consumed because is limitng reactant and there are produced:

0.600mol C2H4 * (2 mol CO2 / 1mol C2H4) = 1.200 moles of CO2

0.600mol C2H4 * (2 mol H2O / 1mol C2H4) = 1.200 moles of H2O

And 2.400 mol of Ne that doesn't react.

Total moles are:

0.900mol + 1.200mol + 1.200mol + 2.400mol = 5.700mol

Mole fraction O2 = 0.900mol / 5.700mol = 0.1579

Mole fraction CO2 = 1.200mol / 5.700mol = 0.2105

Mole fraction H2O = 1.200mol / 5.700mol = 0.2105

Mole fraction Ne = 2.400mol / 5.700mol = 0.4211

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.