Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Find the smallest perimeter and the dimensions for a rectangle with an area of 36 in squared.

Sagot :

okpalawalter8

Answer:

Therefore the smallest parameters is  (6,6) and a dimension of 24 inches

Step-by-step explanation:

From the question we are told that

area of dimension is  [tex]A=36[/tex]

Generally the perimeter of  rectangle is given as

      [tex]x,y=36[/tex]

Given by

      [tex](x,y)=2x+2y[/tex]

Mathematical solving for perimeter of rectangle

    [tex]x=\frac{36}{y}[/tex]

    [tex]f(y)= 2\frac{36}{2} +2y\\f(y)= \frac{72}{y} +2y[/tex]

Generally in finding minimum perimeter

     [tex]f'(y)=\frac{-72}{y^2} +2=0\\[/tex]

     [tex]y=6[/tex]

[tex]f(6,6)=2(6)+2(6) \\f(6,6)=24 inches[/tex]

Therefore the smallest parameters is  (6,6) and a dimension of 24 inches

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.