Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer: Option C.
Explanation:
When the box is moving, he pushes with a force F.
in this case, the coefficient is μk, and the box is accelerating, this means that the net force is not zero, so F is larger than the friction force.
When the box is still, the man pushes again with a force F, but now the box does not move, so there is no acceleration, which means that the net force is zero, then F is not greater than the maximum static friction force.
Now, the friction force between an object of mass M, and a surface with a coefficient of friction μ is: μ*m*g
where g is the gravitational acceleration.
Then, from the first part, we can conclude that:
μk*m*g < F
(the force F is larger than the kinetic friction force)
and from the second part, we know that:
F ≤ μs*m*g
(The force F is not greater than the static friction force)
If we write those two together, we have:
μk*m*g < F ≤ μs*m*g
Then the correct option is c.
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.