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Sagot :
Answer:
if the angular momentum is constant, the skater is closer, going faster.
w₂ = r₁² / r₂² w₁
Explanation:
For the skaters to perform in the turn in l, the angular number of the same must be equal, so we stammer the concept of conservation of angular momentum
L₁ = L₂
the angular momentum is
L = I w
we substitute
I₁ w₁ = I₂ w₂
w₂ = [tex]\frac{I_{1} }{I_{2} }[/tex] w₁
if we consider the skater as a particle, his moment of inertia is
I = m r²
we substitute
w₂ = r₁² / r₂² w₁
therefore, if the angular momentum is constant, the skater is closer, going faster.
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