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A soccer ball with a mass of 0.427 kg approaches a player horizontally with a speed of 16.0 m/s. The player kicks the ball with her foot, which causes the ball to move in the opposite direction with a speed of 21.7 m/s.

Required:
a. What magnitude of impulse (in kg · m/s) is delivered to the ball by the player?
b. What is the direction of the impulse delivered to the ball by the player?
c. If the player's foot is in contact with the ball for 0.0600 s, what is the magnitude of the average force (in N) exerted on the player's foot by the ball?

Sagot :

Explanation:

Given that,

Mass of a soccer ball, m = 0.427 kg

Initial speed, u = 16 m/s

Final speed, v = -21.7 m/s (negative as it is in opposite direction)

(a) Impulse = change in momentum

J = 0.427 × (-21.7 -16)

J = -16.097 kg-m/s

(b) Impulse delivered to the ball by the player is in opposite direction.

(c) Time of contant, t = 0.0600 s

Average force,

J = force×time

[tex]F=\dfrac{J}{t}\\\\F=\dfrac{16.097}{0.0600 }\\\\=268.28\ N[/tex]

Hence, this is the required solution.

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