Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A scientist uses a submarine to study ocean life she begins at C level which is at an elevation of 0 feet then she travel straight down for 90 seconds at a speed of 3.5 ft./s then she then travels directly up for 30 seconds how do you speed of 2.2 ft./s after this 120 seconds period how much time in seconds will it take for the sciences to travel back to see if level at the submarines maximum speed of 4.8 ft./s

Sagot :

sqdancefan

9514 1404 393

Answer:

  10.625 seconds

Step-by-step explanation:

distance = speed · time

We want the total of all distances to be zero.

  (-3.5)(90) +(2.2)(120) +(4.8)t = 0

  -315 +264 +4.8t = 0 . . . . . simplify

  -51 +4.8t = 0 . . . . . . . . . . . simplify more

  -10.625 +t = 0 . . . . . . . . . .divide by 4.8

  t = 10.625 . . . . . . . . . . . . . add 10.625

It will take the scientist 10.625 seconds to reach sea level.

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.