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Whit is (1/4x + 3/4x + -1/2x) + 1 + -2/3) =

Sagot :

Answer:

[tex]\dfrac{x}{2}+\dfrac{1}{3}[/tex]

Step-by-step explanation:

We need to find the value of [tex]((\dfrac{1}{4}x+\dfrac{3}{4}x-\dfrac{1}{2}x)+1+(\dfrac{-2}{3}))[/tex]

We can solve it as follows :

[tex]((\dfrac{1}{4}x+\dfrac{3}{4}x-\dfrac{1}{2}x)+1+(\dfrac{-2}{3}))\\\\=(\dfrac{x+3x-2x}{4})+1-\dfrac{2}{3}\\\\=\dfrac{2x}{4}+\dfrac{1}{3}\\\\=\dfrac{x}{2}+\dfrac{1}{3}[/tex]

Hence, the value of [tex]((\dfrac{1}{4}x+\dfrac{3}{4}x-\dfrac{1}{2}x)+1+(\dfrac{-2}{3}))[/tex] is equal to [tex]\dfrac{x}{2}+\dfrac{1}{3}[/tex].