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For the reaction C+2H 2 —->CH 4 calculate the percent yield if 98 g of methane is produced when 100. g of carbon reacts with an excess of hydrogen?

Sagot :

ardni313

The percent yield : 73.5%

Further explanation

Given

Reaction

C+2H₂⇒CH₄

Required

The percent yield

Solution

mol of Carbon(as a limiting reactant) :

[tex]\tt \dfrac{100}{12}=8.3[/tex]

mol CH₄ based on C, and from equation mol ratio C : CH₄, so mol CH₄ = 8.3

Mass of Methane(theoretical yield) :

[tex]\tt mass=mol\times MW\\\\mass=8.3\times 16=133.3~g[/tex]

[tex]\tt \%~yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{98}{133.3}\times 100\%=73.5\%[/tex]

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