Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

The area of Mr. Rogers’ field is 3 ⅓ square miles. If the width of the field is ⅔ of a mile, what is the length?

Sagot :

absor201

Answer:

Length of Mr. Roger's field = 5 miles

Step-by-step explanation:

Given that:

Area of Mr. Roger's field = [tex]3\frac{1}{3}=\frac{10}{3}[/tex] square miles

Width of Mr. Roger's field = [tex]\frac{2}{3}[/tex] of a mile

Let,

l be the length of Mr. Roger's field

Area of field = Length * Width

[tex]\frac{10}{3}=\frac{2}{3}l[/tex]

Multiplying both sides by 3/2

[tex]\frac{3}{2}*\frac{10}{3}=\frac{2}{3}l*\frac{3}{2}\\5 = l\\l = 5[/tex]

Hence,

Length of Mr. Roger's field = 5 miles

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.