Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

4 Fe + 3 O2 --> 2 Fe2O3
How many grams of Fe will react with 40.0 grams of O2?

Sagot :

Eduard22sly

Answer:

93.33 g of Fe

Explanation:

The balanced equation for the reaction is given below:

4Fe + 3O₂ —> 2Fe₂O₃

Next, we shall determine the masses of Fe and O₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 4 × 56 = 224 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 3 × 32 = 96 g

SUMMARY:

From the balanced equation above,

224 g of Fe reacted with 96 g of O₂.

Finally, we shall determine the mass of Fe required to react with 40 g of O₂. This can be obtained as follow:

From the balanced equation above,

224 g of Fe reacted with 96 g of O₂.

Therefore, Xg of Fe will react with 40 g of O₂ i.e

Xg of Fe = (224 × 40)/96

Xg of Fe = 93.33 g

Therefore, 93.33 g of Fe is required to react with 40 g of O₂.

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.