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Sagot :
Answer:
New acceleration = 1.5 m/s²
Explanation:
The acceleration of an object when it moves in a circular path is given by :
[tex]a=\dfrac{v^2}{r}[/tex]
Where
v is speed of an object
r is radius of path
If v remains constant,
[tex]a\propto \dfrac{1}{r}[/tex]
or
[tex]\dfrac{a_1}{a_2}=\dfrac{r_2}{r_1}[/tex]
Put r₁ = 5 m, a₁ = 3m/s², r₂ = 10 m
[tex]a_2=\dfrac{a_1r_1}{r_2}\\\\a_2=\dfrac{3\times 5}{10}\\\\a_2=1.5\ m/s^2[/tex]
Hence, if the radius of its path is increased to 10 m, its acceleration will be 1.5 m/s².
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