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What volume (in liters) does 3.91
moles of nitrogen gas at 5.35 atm
and 323 K occupy

What Volume In Liters Does 391 Moles Of Nitrogen Gas At 535 Atm And 323 K Occupy class=

Sagot :

Data Given:
Moles = n = 3.91 mol

Pressure = P = 5.35 atm

Temperature = T = 323 K

Volume = V = ?

Formula used: Ideal Gas Equation is used,

P V = n R T
Solving for V,
V = n R T / P
Putting Values,
V = (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm

V = 19.36 L
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