Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Given:
Consider the given function is
[tex]y=|8x-3|-3[/tex]
To find:
The vertex , axis of symmetry, and transformations of the parent function?
Solution:
We have,
[tex]y=|8x-3|-3[/tex]
[tex]y=\left|8\left(x-\dfrac{3}{8}\right)\right|-3[/tex]
[tex]y=8\left|x-\dfrac{3}{8}\right|-3[/tex] ...(i)
It is an absolute function.
The vertex form of an absolute function is
[tex]y=a|x-h|+k[/tex] ...(ii)
where, a is a constant, (h,k) is vertex and x=h is axis of symmetry.
From (i) and (ii), we get
[tex]a=8,h=\dfrac{3}{8},k=-3[/tex]
So,
[tex]\text{Vertex}:(h,k)=\left(\dfrac{3}{8},-3\right)[/tex]
[tex]\text{Axis of symmetry}:x=\dfrac{3}{8}[/tex]
Parent function of an absolute function is
[tex]y=|x|[/tex]
Since, a=8 therefore, parent function vertically stretched by factor 8.
[tex]h=\dfrac{3}{8}>0[/tex], so the function shifts [tex]\dfrac{3}{8}[/tex] unit right.
k=-3<0, so the function shifts 3 units down.
Therefore, the vertex is [tex]\left(\dfrac{3}{8},-3\right)[/tex] and Axis of symmetry is [tex]x=\dfrac{3}{8}[/tex]. The parent function vertically stretched by factor 8, shifts [tex]\dfrac{3}{8}[/tex] unit right and 3 units down.
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
