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Pre-Calc
Pleas hurry, I don't know what to do

PreCalc Pleas Hurry I Dont Know What To Do class=

Sagot :

Answer:

The slope of the line is 3.

Step-by-step explanation:

Given function;

x(t) = -t² + 5t

y(t) = 3t, when t = 2

[tex]\frac{dx}{dt} = -2t + 5[/tex]

[tex]\frac{dy}{dt} = 3[/tex]

[tex]\frac{dy}{dx}= \frac{dy}{dt} \ \times \ \frac{1}{\frac{dx}{dt} } \\\\\frac{dy}{dx}= 3 \ \times \frac{1}{-2t + 5} \\\\\frac{dy}{dx}= \frac{3}{-2t + 5}[/tex]

t = 2

[tex]Then, \ \frac{dy}{dx}= \frac{3}{-2(2) + 5} \\\\\frac{dy}{dx}= \frac{3}{-4 + 5} \\\\\frac{dy}{dx}= \frac{3}{1} \\\\\frac{dy}{dx}= 3[/tex]

Therefore, the slope of the line is 3.