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A line is perpendicular to y = -x + 1
and intersects the point (-5,1).
What is the equation of this
perpendicular line?

A Line Is Perpendicular To Y X 1 And Intersects The Point 51 What Is The Equation Of This Perpendicular Line class=

Sagot :

Answer:

y = 5x + 26

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - [tex]\frac{1}{5}[/tex] x + 1 ← is in slope- intercept form

with slope m = - [tex]\frac{1}{5}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{5} }[/tex] = 5 , thus

y = 5x + c ← is the partial equation

To find c substitute (- 5, 1) into the partial equation

1 = - 25 + c ⇒ c = 1 + 25 = 26

y = 5x + 26 ← equation of perpendicular line