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A 15-kilogram wagon originally at rest on a level road is pulled by a rope that exerts a constant horizontal force of 45 newton's, If the frictional forces on the wagon total 15 newton's, what will be its acceleration ? *
2.0 〖m/s〗^2
4.0 〖m/s〗^2
15 〖m/s〗^2
30 〖m/s〗^2
3.0 〖m/s〗^2

Sagot :

olayemiolakunle65

Answer:

A. 2 m/[tex]s^{2}[/tex]

Explanation:

Mass of wagon = 15 kg

Horizontal force = 45 N

frictional force = 15 N

It is good to note that part of the exerted horizontal force would be used to overcome the frictional force on the wagon.

So that, total force exerted on the wagon can be determined by;

total force = horizontal force - frictional force

                 = 45 - 15

                 = 30 N

From Newton's second law of motion, we have;

F = ma

Where: F is the force applied on an object, m is its mass, and a is the acceleration of the object.

Thus,

30 = 15 x a

a = [tex]\frac{30}{15}[/tex]

  = 2 m/[tex]s^{2}[/tex]

The acceleration of the wagon is 2 m/[tex]s^{2}[/tex].

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