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Sagot :
Answer:
t = 33 seconds
It is the amount of time when the temperature of the body will rise from 100 to fatal 104 in the absence of sweat.
Step-by-step explanation:
weight of the farmer = 176 lb
Sweating = 1 litre per hour
60% of above sweating is evaporated by the latent heat from farmers body.
Temperature outside = 104
Temperature of the Farmer = 100
Time to rise the temperature 4 degrees = ?
We need to use the specific heat formula to calculate the time to rise the temperature of the body of farmer.
Before, that let's convert weight of the farmer in Kg
W = 176 lb
1 lb = 0.453592 kg
176 lb = 79.8 kg
w = mg
g = 10
mass = m = 79.8/10
mass = 7.98 kg
Q = mc∆T
c = specific heat of water = 4,186
∆T = Temperature Change = 104-100
∆T = 4
Q = 7.98 x 4186 x 4
Q = 133617
t = Q/P
Power of Sun's Heat = 3.846×1026
t = 33 seconds
It is the amount of time when the temperature of the body will rise from 100 to fatal 104 in the absence of sweat.
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