Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

If a radioactive isotope has a half-life of 6 hours and 12 milligrams is initially present, how much will
be present in 24 hours?


Sagot :

Answer:0.75 milligrams will  be present in 24 hours

Step-by-step explanation:

Step 1

The formula for radioactive decay can be written as

N(t)=No (1/2)^(t/t 1/2)

where

No= The amount of the radioactive substance at time=0=milligrams

t 1/2= the half-life= 6 hours

t=24 hours

N(t) = the amount at time t

Step 2--- Solving

N(t)=No (1/2)^(t/t 1/2)

=N(t)=12 x ( 1/2) ^ (24/6)

= 12 x (1/2) ^4

= 12 x 0.0625

= 0.75 milligrams

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.