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Two people decided to race. One of the cars is 10 meters north of the start line 5 seconds into the race. After 15 seconds, the car is 25 meters north of the start line. Calculate the average velocity of the car.

Sagot :

Answer:

The average velocity of the car is 1.5 m/s

Step-by-step explanation:

The given parameters are;

The displacement of one of the cars north of the start after 5 seconds = 10 meters

The displacement of the car north of the start after 15 seconds = 25 meters

The average velocity of the cars [tex]\overline v[/tex] is given as follows;

[tex]\overline v = \dfrac{\Delta x}{\Delta t}[/tex]

Where;

Δx = The change in the displacement of the car = 25 m - 10 m = 15 m

Δt = The corresponding amount of the change in time 15 s - 5 s = 10 s

By substituting the known values of Δx and Δt in the equation for the average velocity of the car, [tex]\overline v[/tex], we have;

[tex]\overline v = \dfrac{15 \ m}{10 \ s} = 1.5 \ m/s[/tex]

∴ The average velocity of the car, [tex]\overline v[/tex] = 1.5 m/s

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