nwade5
Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

What is the KE of a 13kg boulder moving at 78.3m/s?

Sagot :

Answer:

39850.785 J

Explanation:

0.5 x m x v^2

0.5x13x78.3^2

NusrathC

Answer:

KE =

[tex] \frac{1}{2} m {v}^{2} \\ [/tex]

Explanation:

[tex]ke = \frac{1}{2} m {v}^{2} \\ = \frac{1}{2} \times 13 \times {78 . 3}^{2} \\ ke = 39850.785j \\ [/tex]

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.