nwade5
Answered

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What is the KE of a 13kg boulder moving at 78.3m/s?

Sagot :

Answer:

39850.785 J

Explanation:

0.5 x m x v^2

0.5x13x78.3^2

NusrathC

Answer:

KE =

[tex] \frac{1}{2} m {v}^{2} \\ [/tex]

Explanation:

[tex]ke = \frac{1}{2} m {v}^{2} \\ = \frac{1}{2} \times 13 \times {78 . 3}^{2} \\ ke = 39850.785j \\ [/tex]

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